Bzoj3514:codechef MARCH14 GERALD07 Enhanced Edition

Source: Internet
Author: User

Description

An l,r graph of n-point m-bars, asking for the number of Unicom blocks in the graph when the number on the edge of [] is reserved.

Input

The first line is four integers n, M, K, type, representing the number of points, number of sides, query, and whether to ask for encryption.
The next m line represents each edge in the diagram.
The next K line, two integer l, R for each line, represents a set of queries. For type=0 test points, L and R that are read in are the L, R for the inquiry, and for type=1 test points, the L and R for each group should be L XOR Lastans and R xor Lastans.

Output

K lines each line of an integer represents the number of unicom blocks queried by the group.

Sample Input3 5 4 0
1 3
1 2
2 1
3 2
2 2
2 3
1 5
5 5
1 2
Sample Output2
1
3
1
HINT

For 100% of data, 1≤n, M, k≤200,000.

Puzzle: Http://hzwer.com/4358.htmlcode:
1#include <cstdio>2#include <iostream>3#include <cmath>4#include <cstring>5#include <algorithm>6 using namespacestd;7 Charch;8 BOOLOK;9 voidReadint&x) {Ten      for(ok=0, Ch=getchar ();! IsDigit (CH); Ch=getchar ())if(ch=='-') ok=1; One      for(x=0; isdigit (ch); x=x*Ten+ch-'0', ch=GetChar ()); A     if(OK) x=-x; - } - Const intmaxn=400005; the Const intMaxnode=4000000; - Const intinf=2147483647; - intN,m,q,type,a[maxn],b[maxn],l,r,pos[maxn],pop[maxn],root[maxn],ans; - structlct{ +     intson[maxn][2],FA[MAXN],VAL[MAXN],MINV[MAXN],POS[MAXN],ID[MAXN],REV[MAXN]; -     voidInitintXintVinti) {val[x]=minv[x]=v,pos[x]=id[x]=i;} +     intWhich (intx) {returnson[fa[x]][1]==x;} A     BOOLIsRootintx) {returnson[fa[x]][0]!=x&&son[fa[x]][1]!=x;} at     voidReverseintx) {if(x) rev[x]^=1;} -     voidPushdown (intx) {if(Rev[x]) swap (son[x][0],son[x][1]), Reverse (son[x][0]), Reverse (son[x][1]), rev[x]=0;} -     voidRelaxintx) {if(!isroot (x)) relax (fa[x]); Pushdown (x);} -     voidUpdateintXintY) {if(Minv[x]>minv[y]) minv[x]=minv[y],pos[x]=pos[y];} -     voidUpdateintx) { -minv[x]=val[x],pos[x]=Id[x]; in         if(son[x][0]) Update (x,son[x][0]); -         if(son[x][1]) Update (x,son[x][1]); to     } +     voidRotateintx) { -         intY=fa[x],z=fa[y],d=which (x), dd=which (y); thefa[son[x][d^1]]=y,son[y][d]=son[x][d^1],fa[x]=Fa[y]; *         if(!isroot (y)) son[z][dd]=x; $son[x][d^1]=y,fa[y]=x,update (y), update (x);Panax Notoginseng     } -     voidSplay (intx) { the relax (x); +          while(!isroot (x)) { A             if(IsRoot (fa[x])) rotate (x); the             Else if(which (x) = =which (fa[x]) rotate (fa[x]), rotate (x); +             Elserotate (x), rotate (x); -         } $     } $     voidAccessintx) { for(intp=0; x;x=fa[x]) splay (x), fa[son[x][1]=p]=x,update (p=x);} -     voidMake_root (intx) {Access (x), splay (x), reverse (x);} -     intFindintx) { the access (x), splay (x); -          for(; son[x][0];x=son[x][0]) pushdown (x);Wuyi         returnx; the     } -     intQueryintXinty) { Wu         if(Find (x) ==find (y)) {make_root (x), Access (y), splay (y);returnpos[y];} -         Else return 0; About     } $     voidCutintXintY) {make_root (x), Access (y), splay (y), fa[x]=0, son[y][0]=0;} -     voidLinkintXintY) {make_root (x), fa[x]=y;} - }LCT; - structseg{ A     inttot,sum[maxnode],son[maxnode][2]; +     voidInsertintPint&k,intLintRintx) { thesum[k=++tot]=sum[p]+1; -         if(L==R)return; $         intM= (l+r) >>1; the         if(x<=m) son[k][1]=son[p][1],insert (son[p][0],son[k][0],l,m,x); the         Elseson[k][0]=son[p][0],insert (son[p][1],son[k][1],m+1, r,x); the     } the     intQueryintKintLintRintx) { -         if(L==R)returnSum[k]; in         intM= (l+r) >>1; the         if(x<=m)returnQuery (son[k][0],l,m,x); the         Else returnsum[son[k][0]]+query (son[k][1],m+1, r,x); About     } the     intQueryintAintBintx) {returnQuery (b,0, m,x)-query (A,0, m,x);} the }t; the intMain () { + Read ( N), read (m), read (q), read (type); -      for(intI=1; i<=n;i++) Lct.init (I,inf,0); the      for(intI=1; i<=m;i++) Lct.init (n+i,i,i);Bayi      for(intI=1; i<=m;i++){ the read (A[i]), read (B[i]); the         if(a[i]!=B[i]) { -pop[i]=lct.query (A[i],b[i]); -             if(Pop[i]) lct.cut (a[pop[i]],pop[i]+n), Lct.cut (b[pop[i]],pop[i]+n); theLct.link (A[i],n+i), Lct.link (b[i],n+i); the         } the         Elsepop[i]=i; the     } -      for(intI=1; i<=m;i++) T.insert (root[i-1],root[i],0, M,pop[i]); the      while(q--){ the Read (l), read (r); the         if(type) l^=ans,r^=ans;94Ans=n-t.query (root[l-1],root[r],l-1); theprintf"%d\n", ans); the     } the     return 0;98}

Bzoj3514:codechef MARCH14 GERALD07 Enhanced Edition

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