C + + fifth time job

One, array selection from the keyboard input 10 number in the array A, the number of non-repeating in the array in array b #include<iostream>  using namespace std;  int main ()  {      const int n=10;      int a[n],b[n],i,j,k=0;      for (i=0;i<n;i++)      cin>>a[i];      for (i=0;i<n;i++)      {for          (j=0;j<n+1;j++)          {              if (i==j) continue;              if (A[i]==a[j]) break;              if (j==10)              {                 b[k]=a[i];                 k++      ;      }}} cout<< "non-repeating array:";      for (i=0;i<k;i++)      cout<<b[i]<< ",";  return 0;  }  

Second, sum input 10 numbers from the keyboard into array a, and #include<iostream> using namespace std for positive and negative numbers in a array  ;  int main ()  {      const int n=10;      int a[n],i,sum1=0,sum2=0;      cout<< "Input 10 number:";      for (i=0;i<n;i++)      {            cin>>a[i];          if (a[i]>0)          sum1=sum1+a[i];          else if (a[i]<0)          sum2=sum2+a[i];      }      cout<< "positive and;" <<sum1<< "\ n";      cout<< "negative and;" <<sum2;      return 0;  }  

String 0 (large/lowercase) number of letters, number of digits and number of other characters </span> #include <iostream>  #include <cstdio>  using namespace Std;  int main ()  {      char str[50];      int i=0,n=0,j=0,k=0,l=0;      cout<< "input string:";      Gets (str);      while (str[i]!= ')      {          if (str[i]>= ' 0 ' &&str[i]<= ' 9 ')          n++;          else if (str[i]>= ' a ' &&str[i]<= ' Z ')          j + +;          else if (str[i]>= ' A ' &&str[i]<= ' Z ')          k++;          else l++;          i++;      }      cout<< "Number of Numbers:" <<n<<;      cout<< "Number of lowercase letters:" <<j<<;      cout<< "Number of capital letters:" <<k<<;      cout<< "Number of other characters:" <<l;      return 0;  }  

C + + fifth time job