# C # hexadecimal conversion, operators, and expressions (+-*/% I ++, ++ I,

Source: Internet
Author: User

C # hexadecimal conversion, operators, and expressions (+-*/% I ++, ++ I,

// Summary:

* When converting from decimal to other hexadecimal values, we use Convert. ToString (decimal number, the hexadecimal value to be converted );

* Convert. ToInt32 is used to Convert from other hexadecimal to decimal (Other hexadecimal strings, other hexadecimal numbers );

* If the conversion is not in decimal format, use Convert. toString (decimal number, in hexadecimal format); and Convert. toInt32 (Other hexadecimal strings, other hexadecimal numbers,

* In other words: for example, convert binary to octal: first convert binary to decimal, and then convert decimal to octal.

The same applies to the conversion of octal to octal.

1. // decimal to binary

Stringret = Convert. ToString (96, 2 );

Console. WriteLine (ret );

2. // binary to decimal

IntretNum = Convert. ToInt32 ("1100000", 2 );//

Console. WriteLine (retNum );

3. // decimal to octal

Ret = Convert. ToString (96, 8 );

Console. WriteLine (ret );

4. // octal to decimal

RetNum = Convert. ToInt32 ("140", 8 );//

Console. WriteLine (retNum );

Ret = Convert. ToString (96, 16 );

Console. WriteLine (ret );

RetNum = Convert. ToInt32 ("60", 16 );//

Console. WriteLine (retNum );

7. // convert binary data to 8 digits

RetNum = Convert. ToInt32 ("1100000", 2); // binary to decimal

Ret = Convert. ToString (retNum, 8); // decimal to octal

Console. WriteLine (ret );

Ii. Operators and expressions

1. // calculate the right and save the result on the right in the variable.

① Intret = 12 + 15;

Console. WriteLine (ret );

② Ret = 12-15;

Console. WriteLine (ret );

Note the following: * Division summary:

* Integers/integers get integers. If they are not fully divided, the operators are obtained.

* Float-Type Floating Point Numbers/integers get float-Type Floating Point Numbers

* Double-Type Floating-point numbers/integers get double-Type Floating-point numbers

③ Ret = 9/3;

Console. WriteLine (ret );

④ // The integer is divided by the integer. If division is not allowed, the calculation result will be the operator of the two integers.

Ret = 18/4;

Console. WriteLine (ret); // The output result is 4.

// ** Note that the result is correct. Divide the integer by the integer. It can only be a quotient integer.

FloatretFloat = 18/4;

Console. WriteLine (retFloat); // The output result is also 4

⑤ // Divide the decimal number by an integer. The float format must be f

RetFloat = 12.56f/4;

Console. WriteLine (retFloat );

⑥ // The double Type below is also the output decimal point

DoubleretDouble = 12.56/4;

Console. WriteLine (retDouble );

7. ret = 3*9;

Console. WriteLine (ret );

Returns // the remainder of the touch operation.

Ret = 18% 4;

Console. WriteLine (ret );

2,

* Conclusion: I ++ uses the I value before I = I + 1;

* ++ I is the first operation to perform I = I + 1, and then use the value of I

// The following lines of code (1) have the same effect as those of (2), but the output results are also different.

① Console. WriteLine ("---------");

Intnum1 = 10;

Num1 ++; // num1 = num1 + 1;

Console. WriteLine (num1 );

Console. WriteLine ("------**---");

Intnum2 = 10;

+ + Num2; // num2 = num2 + 1;

Console. WriteLine (num2 );

② // The following lines of code differentiate between ++ and before and after, and the output results are different

Console. WriteLine ("*******");

Intnum3 = 10;

// Print the value of num3 before addition.

Console. WriteLine (num3 ++); // output result 10;

Console. WriteLine ("num3 = {0}", num3); // output result 11

Intnum4 = 10;

// First perform addition and then print the value

Console. WriteLine (++ num4); // output result 11

③ Easy to differentiate:

A: intnum5 = 10;

// The following code is equivalent to Console. WriteLine (num5 ++ );

Console. WriteLine (num5); // 10

Num5 = num5 + 1;

B: intnum6 = 10;

// The following code is equivalent to Console. WriteLine (++ num6 );

Num6 = num6 + 1;

Console. WriteLine (num6 );

3. Operation exercises

// Enter a total number of seconds from the console, and the time, minute, and second will be displayed,

// Example

// Enter 86496

// Output 24-hour 1 minute 36 seconds

Console. WriteLine ("Enter the number of seconds ");

Inttime = int. Parse (Console. ReadLine ());

Inthours = time/(60*60 );

Intseconds = time % 60;

Intminute = time % (60*60)/60; // first divided by 3600, it is calculated that it is not enough for an hour, and then divided by 60

Console. WriteLine ("{0} hour {1} minute {2} seconds", hours, minute, seconds );

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