C # How to put the serial port received two bytes, the synthesis of a short integer

c#2013101301

Here are two simple ways to demonstrate:

1. Use the shift character.

Cases:

byte[] bytes = new byte[2]{0x31,0x32};
Short U16;
U16 = (short) ((Bytes[0] << 8) + bytes[1]);
Button1. Text = U16. ToString ();

Come to the result:

hex:3132

dec:12594

2. Use cast, 2nd byte *256

byte[] bytes = new byte[2]{0x31,0x32};
Short U16;
U16 = (short) (short) bytes[0] * 256 + (short) bytes[1];//There must be a cast in the front, because the middle 256 defaults to type int
button1. Text = U16. ToString ();

hex:3132

dec:12594