[C Language] Use arrays, and C Language Use Arrays

[C Language] Use arrays, and C Language Use Arrays

-----------------------------------------------------------------------------

// Main. c example // Created by weichen on 15/1/9. // Copyright (c) 2015 weichen. All rights reserved.
# Include <stdio. h> int main (){
// Calculate the input average int x = 0; // The input number double num = 0; // The sum (this is defined as double, because floating point numbers may appear in the calculation result) int count = 0; // number of double per; // average (the result also defines double) printf ("Enter some numbers:"); scanf ("% d ", & x); // execute cumulatively when the value is greater than 0. Enter a value smaller than or equal to 0 and press enter to terminate the loop. Then, execute the following code while (x> 0) {num + = x; count ++; scanf ("% d", & x) ;}if (count> 0) {per = num/count; printf ("% f \ n", per);} return 0 ;}

 

// Main. c example // Created by weichen on 15/1/14. // Copyright (c) 2015 weichen. All rights reserved.
# Include <stdio. h> int main () {// enter a number, and output the average value and the number greater than the average value. // key point: you need to store the input numbers int x = 0; int n = 0; double total = 0; double per = 0; int number [100]; // 1. define the array printf ("Enter some numbers:"); scanf ("% d", & x); while (x! = 0) {number [n] = x; // 2. array Element assignment total + = x; n ++;} if (n> 0) {per = total/n; printf ("average: % f \ n ", per); printf ("the number greater than the average is:"); for (int I = 0; I <= n; I ++) {if (number [n]> per) // 3. use the array element {printf ("% d \ t", number [I]); // 4. traversing the array }}return 0 ;}

Note: After compiling in Xcode, enter the number and press Enter. line number [n] = x returns the Thread1: EXC_BAD_ACCESS (code = 2, address = 0x7fff5fc00000) error. Does anyone know the cause?

 

// Main. c example // Created by weichen on 15/1/19 // Copyright (c) 2015 weichen. All rights reserved.
# Include <stdio. h> int main (){
// Enter a number in the range of 0-9 to calculate the number of times each number is entered
Const int number = 9; // 1. array size int x; int count [number]; // 2. defines the array int I; for (I = 0; I <= number; I ++) {count [I] = 0; // 3. initialize the array} printf ("Enter:"); scanf ("% d", & x); while (x! =-1) {if (x> = 0 & x <= 9) {count [x] ++; // 4. array involved in calculation} scanf ("% d", & x) ;}for (I = 0; I <= number; I ++) {printf ("% d: % d \ n ", I, count [I]);} return 0 ;}

 

// Main. c one-dimensional array // Created by weichen on 15/1/28. // Copyright (c) weichen. All rights reserved.
# Include <stdio. h> int main () {/* 1. array integration initialization int a [] = {1, 2, 6, 7, 9}; for (int I = 0; I <5; I ++) {printf ("% d \ t", a [I]);} */
/* 1. declare an array with a length of 12. The first element is assigned a value of 1, and the rest is 0 int a [12] = {1}; for (int I = 0; I <12; I ++) {printf ("% d \ t", a [I]);} * // * 2. do not use loops. initialize the array int a [12] = {0 };*/
/* 2. positioning int a [12] = {[1] = 2, 3, [4] = 9} during Integration initialization }; if [x] is used to locate the unlocated data when initializing the data, the value of other positions following the previous one can be supplemented with 0 or the array size is not given, make compiler operations suitable for initializing sparse arrays {for (int I = 0; I <12; I ++) {printf ("% d \ t", a [I]); // 0 2 3 0 9 0 ....}
}*/
/* 3. array assignment */int a [] = {1, 3}; int length = sizeof (a)/sizeof (a [0]); int B [length]; // 1. the array variable itself cannot be assigned a value, for example, int B [] = a; error // 2. to give the value of an array to another array, you must use traversal, as shown below: for (int I = 0; I <length; I ++) {B [I] = a [I];}
{For (int I = 0; I <length; I ++) {printf ("% d \ t", a [I]); // 0 2 3 0 9 0 ....}}
// Function of traversing the array: // 3. assign values, initialize values, and determine whether the values exist. Count // 4. After the loop is left, I cannot access the array element return 0 as a subscript ;}

 

/*** Thinking question: Find whether a value exists in the array * @ weiChen */# include <stdio. h> int main () {int a [] = {1, 3, 4, 8, 0, 34}; int key; int length = sizeof () /sizeof (a [0]); printf ("enter a number:"); scanf ("% d", & key); int location = search (key,, length); if (location! =-1) {printf ("key: % d exist in array. \ N ", key);} the key: % d does not exist in else {printf (" array. \ N ", key);} return 0;}/*** function: locate the location of the key in the array * @ param key location * @ param a array * @ param length array length * @ return returns the location of the array, otherwise, the system returns-1 ** int search (int key, int a []; int length); */int search (int key, int a [], int length) {for (int I = 0; I <length; I ++) {if (a [I] = key) {return I; break ;}} return-1;
}

 

// Main. c multi-dimensional array // Created by weichen on 15/1/30. // Copyright (c) weichen. All rights reserved.
# Include <stdio. h> int main (int argc, const char * argv []) {// two-dimensional array, three-row five-column matrix int a [3] [5]; for (int I = 0; I <3; I ++) {for (int j = 0; j <3; j ++) {a [I] [j] = I * j ;}} // initialize the two-dimensional array int B [] [5] = {1, 2, 3, 4, 5}, {3, 4, 5, 6, 8 },}; // 1. the number of columns is required, and the number of rows can be measured by the compiler. // 2. one {} for each row, separated by commas // 3. the last comma can exist. There is an old tradition // 4. if omitted, it indicates zero completion // 5. you can also use the location (C99 ONLY) // int c [] [3] ={{ 0}, {1}, {2}; // three rows and three columns, auto-completion for each column // printf ("% d", c [1] [2]); int d [] [3] = {1, 2, 4, 5, 6, 7, 8, 9, 3,}; // initialized to 3 columns, automatically divided into three rows: int I, j, k = 2; for (I = 0; I <3; I ++) {printf ("% d", d [k] [I]); // cyclically Output d [2] [I]} return 0 ;}

 

Link: http://www.cnblogs.com/farwish/p/4212336.html

@ Blackeye poet <www. chenwei. ws>