C language-' ^ ': illegal, right operand have type ' double '

Error code
int pi () {double p=0,j=0;double pi=0;  P =1/(4*j-1);  for (int i=0;i<100000;i++)  {pi=-( -1) ^j*p+pi;printf ("%lf", 4*pi);  }  return 0;} void Main () {//Piint pi ();
}

Wrong reason: pi=-( -1) ^j*p+pi; The mathematical expression cannot be processed directly in C, and the math function needs to be called, and the C-language thinking may not be fully accepted.

Correct code
void Pi2 () {    double p=0,j=1;    int i;    for (i=1;i<10000;i++)  //Here I is the number of items    {        J=pow ( -1.0,i+1)/(2*i-1);  The POW (x, y) is used to calculate the y power of x        p+=j;        printf ("%lf\n", 4*p);  Output the value of each item    }    printf ("%lf\n", 4*p);  Output final PI value   //return 0;} void Main () {//Seek pi   pi2 ();}

　　

C language-' ^ ': illegal, right operand have type ' double '