C Language Applet How to judge the difference between two dates _c language

Source: Internet
Author: User
Tags date1 diff
1. The common wording
Copy Code code as follows:

#include <stdio.h>
int leapyear (int year)
{
if ((year%4==0 && year%100!=0) | | | year%400==0)
return 1;
Else
return 0;
}
int days (int *day1, int *day2)
{
int i=0;
int *tmp;
int diff = 0;
const int MONTH[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
if (day1[0] = = Day2[0])
{
if (day1[1] = = day2[1])
{
diff = day1[2]-day2[2];
diff = (diff < 0)? (-diff):d iff;
}
Else
{
if (Day1[1] < day2[1])//day1=1991-5-8 day2=1991-6-2
{
TMP = Day1; Day1=1991-6-2 day2=1991-5-8
Day1 = Day2;
Day2 = tmp;
}
for (i=day2[1]+1; i<day1[1]; i++)
{
diff + + month[i];
}
diff + = month[day2[1]]-day2[2] + day1[2];
if (Day2[1] <= 2 && day1[1] >2)
if (Leapyear (day2[0]))
diff++;
}
}
Else
{
if (Day1[0] < day2[0])
{
TMP = Day1;
Day1 = Day2;
Day2 = tmp;
}
for (i=day2[0]+1; i<day1[0]; i++)
{
if (Leapyear (i))
diff + + 366;
Else
diff + + 365;
}
For (i=day2[1]+1 i<=12; i++)//day1=1992-1-1 day2=1991-1-1
{
diff + + month[i];
}
diff = = (month[day2[1]]-day2[2]);
if (Day2[1] <= 2)
if (Leapyear (day2[0]))
diff++;
for (I=1; i<day1[1]; i++)
{
diff + + month[i];
}
diff + + day1[2];
if (Day1[1] > 2)
if (Leapyear (day1[0]))
diff++;
}
return diff;
}
int main ()
{
int day1[3], day2[3];
int day = 0;
printf ("Enter Date:");
scanf ("%d-%d-%d", &day1[0], &day1[1], &day1[2));
printf ("Enter another date:");
scanf ("%d-%d-%d", &day2[0], &day2[1], &day2[2));
Day = Days (Day1, day2);
printf ("There are%d days between two dates.") \ n ", day);
return 0;
}

2. Use the structure, the code is more tidy some
Copy Code code as follows:

#include <stdio.h>
typedef struct DATE
{
int year;
int month;
int day;
}date;
int leapyear (int year)
{
if ((year%4==0 && year%100!=0) | | | year%400==0)
return 1;
Else
return 0;
}
int compare (date *d1, date *d2)//If the first date is larger than the second date, swap date
{
DATE *tmp;
if (d1->year = = d2->year)//year equal
{
if (D1->month > D2->month)//number of months equal
{
TMP = D1;
D1 = D2;
D2 = D1;
}
else if (D1->month = = d2->month)//Date equal
{
if (D1->day > D2->day)
{
TMP = D1;
D1 = D2;
D2 = D1;
}
}
}
else if (D1->year > D2->year)
{
TMP = D1;
D1 = D2;
D2 = tmp;
}
return 0;
}
int diff (Date *date1, date *date2)
{
int i;
int diff = 0;
const int MONTH[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
if (date1->year = = date2->year)
{
if (Date1->month = = Date2->month)
{
diff = date2->day-date1->day;
}
Else
{
For (i=date1->month+1; i<date2->month; i++)
{
diff + + month[i];
}
diff + + month[date1->month]-date1->day + date2->day;
if (Leapyear (date1->year))
if (date1->month <=2 && date2->month >2)
diff++;
}
}
Else
{
For (i=date1->year+1; i<date2->year; i++)
{
if (Leapyear (i))
diff + + 366;
Else
diff + + 365;
}
For (i=date1->month+1; i<=12; i++)//date1 How many days from the end of the year
{
diff + + month[i];
}
diff + + month[date1->month]-date1->day;
if (Date1->month <= 2)
if (Leapyear (date1->year))
diff++;
For (I=1 i<date2->month; i++)//date2 distance from the beginning how many days
{
diff + + month[i];
}
diff + + date2->day;
if (Date1->month > 2)
if (Leapyear (date2->year))
diff++;
}
return diff;
}
int main ()
{
int days = 0;
DATE Day1, Day2;
DATE *date1, *date2;
Date1 = &day1;
Date2 = &day2;
printf ("Enter Date:");
scanf ("%d-%d-%d",& (Date1->year), & (Date1->month), & (Date1->day));
printf ("Enter another date:");
scanf ("%d-%d-%d", &date2->year, &date2->month, &date2->day);
Compare (Date1, date2);
Days = diff (Date1, date2);
printf ("There are%d days between two dates.") \ n ", days);
return 0;
}

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