C Language Judgment Common year/leap year

Requirements:

After the user enters the year, determine whether the input is common year or leap years

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

Intmain (void)

{

       // Defining Variables

int year = 0;

int temp = 0;

int temp1 = 0;

       // Prompt user to enter year

printf (" Please enter the year:");

scanf ("%d", &year);

       // first determine whether the current year is a whole or a full thousand

temp = year% 100;

       // If the year is full or full thousand, use the - as a divisor

if (temp = = 0)

{

Temp1 = year% 400;

if (Temp1 = = 0)

{

printf ("%d years is a leap year \ n";

}

Else

{

printf ("%d is common year \ n", year);

}

}

Else

{

Temp1 = year% 4;

if (Temp1 = = 0)

{

printf ("%d years is a leap year \ n";

}

Else

{

printf ("%d is common year \ n", year);

}

}

System ("pause");

return 0;

}

C Language Judgment Common year/leap year