C language Output 1-n-bit maximum integer

/*1. Print 1 to the maximum number of n digits. Title: Enter the number n, in order to print out from 1 to the largest number of n decimal digits. For example: Enter 3, then print out 1, 2, 31 until the maximum 3 digits 999. [Trap]: The easiest way to think about this topic is to find the maximum number first. Then the loop output is ready. */#include <stdio.h>//think of the method, from a[0]-a[n] sequentially output each bit, one output only one bit of a number Int main () {int i = 0,j  = 0,k = 0,input=3;//i for the control carry   j for each bit output (bit, 10 bits, etc.)//k for loop carry,input  for maximum output number char  a[] =  "100000000";//Analog Carry Storage while  (J < input)//Determine whether to end {while  (j >= &NBSP;0)//control output of a bit {printf ("%c", A[j]);//output one digit if  (j == 0)  //j==0 for bits   increments {if  (a[j ] ==  ' 9 ')//digit 9 {for  (k = 0; k < input;)//Whether multiple carry {if  (A[k+1] < ' 9 ') {a[k + 1]++;a[k] =  ' 0 ';if  (a[k + 1] ==  ' 1 ' &&i< k+1) i++;//opens a new number of digits break;} else{a[k] =  ' 0 ';//single-digit 0 k++;}}} elsea[0]++;//}j--;//j  from high   down}printf (" ")  //split   each number j = i;//let J be the current highest bit   For example  10  j=i=1;}return 0 after:9 ;} #include<stdio.h> #include <string.h> #include <assert.h>int add_num (Char *arr,int num, int end)//Online general logic analog Digital accumulation program (slightly different) {                                       //num   output digits n  end   analog space Max assert (arr); int is_carry = 0;//whether carry int is_over = 1;//is exceeded with overflow int i = end-1; char *arr1 = arr;if  (arr1[i] != 9) {arr1[i]++;} else{is_carry = 1;arr[i] = 0;while  (1) {if  (end-1 -  (i - 1)  >= num | |  i == 0) {printf ("\n   ****   output ends!  ****\n "); is_over = 0;return is_over;} if  (arr1[--i] != 9) {arr1[i] += is_carry;is_carry = 0;break;} else{arr1[i] = 0;}}}} Void show_num (Char *arr,int num)//Bitwise output {int is_high = 0;while  (num>0) {if   (*arr == 0&&is_high==0) arr++;else{printf ("%d", (int) *arr++); is_high = 1;} num--;} printf (" ");} Int main () {char num[11] = {  '  };while  (Add_num (num, 3,11)) {Show_num (num,11);} return 0;}

C language Output 1-n-bit maximum integer