C language programming: Turning numbers over

C language programming: Turning numbers over

Method 1: (easy to understand)

 

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Int main () {int n; scanf ("% d", & n); // enter the number int result = 0; // Save the flipped result while (1) // while (true) can also be {int I = n % 10; // The result = result * 10 + I is obtained at each time. n = n/10; // recursive downgrading if (n = 0) {break ;}} printf ("the number after the flip is % d \ n", result );}

  

 

Method 2 (modular design, as if Baidu's interview questions)

 

 

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// Obtain the number of digits of an integer int getWei (int num) {int wei = 0; for (int iNum = num; iNum/= 10) // remove the digit {printf ("% d \ n", iNum) in sequence; // print the digit wei ++ after the digit is removed in sequence;} return wei ;} int get10 (int n) {int res = 1; for (int I = 0; I