C language to find the number of uppercase letters in a string, the number of words, the number of substrings and whether an integer is a palindrome number

#include <stdio.h>

#include <ctype.h>

#pragma mark counts the number of characters in each letter entered from the terminal. Use the # sign as the input end flag

int main ()

{

int num[26] = {0}, I; char c;

while ((c = GetChar ()) = = ' # ') {

if (Isupper (c)) {

num[c-65]++;

}

}

for (int i = 0; i<26; i++) {

if (Num[i]) {

printf ("%c:%d\n", i+65, Num[i]);

}

}

return 0;

}

#pragma mark counts the number of words in a line of characters

int main ()

{

Char s[81];

int I, c, num=0,word=0;

Gets (s);

for (i=0; (c=s[i])! = ' + '; i++) {

/* One: judging */

if (c = = 32) {

word++;

}else continue;

}

/* Two: judging */

if (c== ') word = 0;

else if (word==0) {word=1; num++;}

printf ("There is%d words.\n", word);

return 0;

}

#include <stdio.h>

#pragma mark counts the number of occurrences of a string of substrings

int main ()

{

int I, j, K,count;

Char str1[20],str2[20];

printf ("Zhu Chuan:");

Gets (STR1);

printf ("Zi Chuan:");

Gets (STR2);

Count = 0;

for (i=0;str1[i];i++)

for (j=i,k=0;str1[j]==str2[k];j++,k++)

if (!str2[k+1])

count++;

printf ("Chuxian cishu=%d\n", count);

}

#pragma mark asks if an integer is a palindrome number

#include <stdio.h>

int main ()

{

Long num;

int array[10];

scanf ("%ld", &num);

int n = num, k = 0;

do {

Array[k] = n%10;

k++;

n = N/10; Completed the progression of the numbers on a single digit

} while (n!=0);

int i = 0;

int flag = 0;

for (; i< (k-1)/2; i++) {

if (array[i] = = Array[k-1-i]) {flag = 1;}

}

if (flag) {

printf ("%ld is palindrome", num);

}else{

printf ("%ld is not a palindrome", num);

}

}

C language to find the number of uppercase letters in a string, the number of words, the number of substrings and whether an integer is a palindrome number