Calculates the day of the week that is part of the year, and the time between Monday and Sunday.

Resources:

　　The week algorithm refers to the method defined by ISO8601, if you have questions about this, please see: http://en.wikipedia.org/wiki/ISO_week_date

JS Code implementation:

var normalyear = [0,31,59,90,120,151,181,212,243,273,304,334];
var leapyear = [0,33,60,91,121,152,182,213,244,274,305,335];

　　　　　　var nowdate = new Date ();

var datestr = Nowdate.format (' yyyy-mm-dd ');

var year = parseint (datestr.substring (0,4));

var mon = parseint (datestr.substring (5,8));

var day = parseint (datestr.substring (8,10));

var Numberofweek = parseint (Nowdate.getday ()); //

var orginday = 0;
if (Isleapyear (year)) {
Orginday = normalyear[numberofweek+1] + day;
}else{
Orginday = leapyear[numberofweek+1] +day;
}
var weekNum = (Orginday-numberofweek +10)/7; This is the result, which week of the year
WeekNum = weeknum.tostring (). substring (0,weeknum.tostring (). IndexOf ("."));
if (Numberofweek = = 0) {
Begtime = Begtime.add (-(1000*60*60*24) *6). Format (' Yyyy-mm-dd ');
EndTime = Endtime.format (' yyyy-mm-dd ');
}else{
Begtime = Begtime.add (-((1000*60*60*24)) * (numberOfWeek-1)). Format (' Yyyy-mm-dd ');
EndTime = Endtime.add (((1000*60*60*24)) * (7-numberofweek)). Format (' Yyyy-mm-dd ');
}
Begtime, endTime means the time of the week from Monday to the weekend.

　　　　　　function Isleapyear (year) {//To determine if a leap year

if ((year%4) ==0 && (Year%100!=0)) | | (Year% 400 = = 0)) {

return true;
}
return false;
}

Calculates the day of the week that is part of the year, and the time between Monday and Sunday.