Calculation of ROR assembly

Set (ax) = 5, (BX) = 3, (CX) = 2, run the following program section, (ax) = lop: ror BX, cl adc ax, BX loop lop how does ror shift? Thank you.

Ror is the circular right shift command, which shifts the entire right of the destination operand from the number of digits specified by the source operand. The removed bits are refilled to the left blank bits and moved to the flag bits. For example, in this question, (BX) = 3, (CX) = 2 3 is converted to a binary number of 100000011b. After the first bit is shifted to the right of the loop, it is converted to: 10000001b; after the first bit is shifted to the right of the loop, after the first execution of the loop body (BX) = 0c000h, you must note that when the second round is shifted to the right, the carry mark position. Program segment lop: ror BX, cl adc ax, BX loop lop after execution, (ax) = 2006 h
Best Answer
Ror is the circular right shift command, which shifts the entire right of the destination operand from the number of digits specified by the source operand. The removed bits are refilled to the left blank bits and moved to the flag bits. For example, in this question, (BX) = 3, (CX) = 2 3 is converted to a binary number of 100000011b. After the first bit is shifted to the right of the loop, it is converted to: 10000001b; after the first bit is shifted to the right of the loop, after the first execution of the loop body (BX) = 0c000h, you must note that when the second round is shifted to the right, the carry mark position. Program segment lop: ror BX, cl adc ax, BX loop lop after execution, (ax) = 2006 h