Calculation Order of variable parameters of printf function under Linux system

Source: Internet
Author: User

 #include <stdio.h> void main ()  { int i=5;  //printf ("%d,%d,\n", i,i++),  //output  6,5,//printf ("%d,%d,\n", i++,i);  //output  6,6,//printf (" %d,%d,\n ", i,++i);  //output  6,6,//printf ("%d,%d,\n ", ++i,i);  //output  6,6,//printf ("%d,%d,\n ", i++,++ i);  //output  6,7,//printf ("%d,%d,\n", ++i,i++)  //output  7,5,//printf ("%d,%d,\n", i++,i++);  // Output  6,5,//printf ("%d,%d,\n", ++i,++i),  //output  7,7,//This is derived: The variable parameter is calculated from right to left, and post-increment (i++) is to first save the I current value, and then self-increment, Then proceed to the left argument. And I and I before self-increment is calculated first. After the calculation is completed sequentially into the stack, so after the self-increment printing is I in the right-to-left calculation process of the current I value, and i,++i final output is the final value of I. Therefore://printf ("%d,%d,%d,%d,\n", ++i,i++,++i,i);  //output  8,6,8,8,//printf ("%d,%d,%d,%d,\n", ++i,++i,++i,++i) ;  //output  9,9,9,9,//printf ("%d,%d,%d,%d,\n", i++,i++,i++,i++)  //output  8,7,6,5,//printf ("%d,%d,%d ,%d,%d,\n ", i++,++i,i,++i,i++);  8,9,9,9,5,} 


Calculation Order of variable parameters of printf function under Linux system

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