Description
An inch worm was at the bottom of a well n inches deep. It has enough-climb u inches every minute, but then have to rest a minute before climbing again. During the rest, it slips down d inches. The process of climbing and resting then repeats. How long before is the worm climbs out of the well? We ' ll always count a portion of a minute as a whole minute and if the worm just reaches the top of the well at the end of Its climbing, we'll assume the worm makes it out.
Input
There'll be multiple problem instances. Each line would contain 3 positive integers n, u and D. These give the values mentioned in the paragraph above. Furthermore, assume D < u and N < 100. A value of n = 0 indicates end of output.
Output
Each input instance should generate a single integer on a line, indicating the number of minutes it takes for the worm to Climb out of the well.
Sample Input
10 2 120 3 10 0 0
Sample Output
1719
#include <iostream>#include<cstdio>#include<cstring>#include<algorithm>using namespacestd;intMain () {#ifdef cdzsc_offline freopen ("In.txt","R", stdin);#endif intN,u,d,sum,ans; while(SCANF ("%d%d%d", &n,&u,&d) &&n!=0&&u!=0&&d!=0) {sum=0, ans=0; while(sum+u<n) {sum+=u-D; Ans+=2; } printf ("%d\n", ans+1); } return 0;}
View Code
Cdzsc_2015 new Winter Holiday (1)--Basic F