CF 4 exercises

Source: Internet
Author: User

A

B

C

Question

 

D: N binary groups. Find the longest sequence group seq. The values of each element in the sequence are greater than those of the previous element.

You can use either the memory-based search or the filtered DP.

Two methods

View code

# Include <cstdio> # Include <Cstring> # Include < Set > # Include < String > # Include <Iostream> # Include <Map> # Include <Vector> # Include <Algorithm> Using   Namespace  STD;  # Define Debug printf ("buuug \ n "); Const   Int Maxn = 5010  ;  Const   Int INF = ~ 0u > 1  ;  Int DP [maxn], NXT [maxn];  Struct  Node {  Int  W, H;} p [maxn];  Int  N, ans;  Int DFS ( Int  Pos ){  If (DP [POS]) Return  DP [POS]; DP [POS] = 1  ;  For ( Int I = 0 ; I <= N; I ++ ){  If (P [I]. W> P [POS]. W & P [I]. h> P [POS]. h ){  If (DFS (I) + 1 > DP [POS]) {NXT [POS] = I; DP [POS] = DP [I] + 1  ;}}}  Return DP [POS];}  Int  Main (){  Int  I, J, K; scanf (  "  % D  " ,& N );  For (I = 0 ; I <= N; I ++ ) Scanf (  "  % D  " , & P [I]. W ,&P [I]. H); memset (NXT, - 1 , Sizeof  (NXT); DFS (  0  ); Printf (  "  % D \ n  " , DP [ 0 ]- 1  );  For (I = NXT [ 0 ]; I! =- 1 ; I =NXT [I]) {printf (  "  % D  "  , I);} puts (  ""  );  Return   0  ;} 

 

View code

# Include <cstdio> # Include <Cstring> # Include < Set ># Include < String > # Include <Iostream> # Include <Map> # Include <Vector> # Include <Algorithm> Using   Namespace  STD;  # Define Debug printf ("buuug \ n "); Const   Int Maxn = 5010 ;  Const   Int INF = ~ 0u > 1  ;  Int  DP [maxn], Fa [maxn], ne [maxn];  Int  A [maxn];  Struct  Node {  Int  W, h;  Int  ID;} p [maxn]; Int  CMP (node A, Node B ){  If (A. W! = B. W) Return A. W < B. W;  Return A. H < B. H ;}  Int  N, ans;  Int  Main (){  Int  I, J, K, W, H; scanf (  "  % D  " ,& N); scanf (  "  % D  " , & W ,& H );  Int TOT = 0  ;  For (I = 1 ; I <= N; I ++ ) {Scanf (  "  % D  " , & P [I]. W ,& P [I]. H ); If (P [I]. W> W & P [I]. h> H) {P [ ++ Tot] = P [I]; P [tot]. ID = I ;}}  If (TOT = 0  ) {Puts (  "  0  "  );  Return   0  ;} P [  0 ]. ID = 0 ; DP [ 0 ] = 1  ; Sort (P + 1 , P + tot + 1  , CMP); memset (FA, - 1 , Sizeof  (Fa ));  Int  End;  For (I = 1 ; I <= tot; I ++) {DP [I] = 1  ;  For (J = 1 ; J <I; j ++ ){  If (P [J]. W <p [I]. W & P [J]. H <p [I]. H & DP [J] + 1 > DP [I]) {DP [I] = DP [J] + 1 ; Fa [I] = J ;}}  If (DP [I]> ans) ans = DP [I], end =I;} printf (  "  % D \ n  " , ANS ); Int TMP = Ans;  While (End! =- 1  ) {A [TMP --] = P [end]. ID; End = Fa [end];}  For (I = 1 ; I <= ans; I ++) printf ( " % D  "  , A [I]);  //  Scanf ("% d", & N );      Return   0  ;}  /*  6 1 1900000 900000902400 902400901200 901200903600 903600906000 906000904800 904800  */ 

 

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