Classroom Practice--"Find the water king continued"

Source: Internet
Author: User

Design ideas:

① as in the last train of thought, simplify the problem to find the 3 most frequently occurring number of occurrences from an array.

② will "22 phase elimination" Mode of thinking into "31 phase elimination"

③ initializes time to zero, Kingid is zero, then assigns values sequentially, encounters the same time1+1 as KINGID1, the remaining two are the same, and encounters all time-1 that differ from three.


Import java.util.*; Public classFindthreenum { Public Static voidMain (string[] args) {Scanner input=NewScanner (System.inch); System. out. println ("Please enter the length of the array:"); intLength =Input.nextint (); int[] id =New int[length]; System. out. println ("Please enter an array:");  for(intI=0; i<length;i++) {Id[i]=Input.nextint ();                } input.close (); intkingid1=0; intKingid2=0; intkingid3=0; inttime1=0; intTime2=0; inttime3=0;  for(intI=0; i<length;i++)        {            if(time1==0&& Id[i]!=kingid2 && id[i]!=kingid3) {KINGID1=Id[i]; Time1++; }            Else if(time2==0&& id[i]!=kingid1 && id[i]!=kingid3) {Kingid2=Id[i]; Time2++; }            Else if(time3==0&& id[i]!=kingid1 && id[i]!=Kingid2) {KINGID3=Id[i]; Time3++; }            Else if(Id[i]!=kingid1 && Id[i]!=kingid2 && id[i]!=kingid3) {time1--; Time2--; Time3--; }            Else if(id[i]==kingid1) {time1++; }            Else if(id[i]==Kingid2) {time2++; }            Else if(id[i]==kingid3) {Time3++; }} System. out. println ("The Water kings were:"+ KINGID1 +","+ Kingid2 +","+kingid3); }}



This class of practice compared to the last time to feel bad, that is, the number of times to change from one to three, so still take the last thought to do it is not very difficult.

Classroom Practice--"Find the water king continued"

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