Code for the three-mesh operator and array method in Java and the size of the integer comparison

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code block

The code is as follows, for example:

class, imported Java package Import java.util.scanner;//I only have the main method listed public static void Main (string[] args) {Scanner Scanner = NE        W Scanner (system.in);                Receive user input System.out.println ("Clear input 1th number:");                int a = Scanner.nextint ();                SYSTEM.OUT.PRINTLN ("Clear input 2nd number:");                int b = Scanner.nextint ();                SYSTEM.OUT.PRINTLN ("Clear input 3rd number:");                int c = Scanner.nextint ();                SYSTEM.OUT.PRINTLN ("Clear input 4th Number:");        int d = Scanner.nextint (); The trinocular operation solves int m = a > B?        A:B; int n = c > d?        C:d; int x = m > n?        m:n;        System.out.println ("max=" + x);                The branching method solves the int t;  if (a > B) {t = A;  A = b;              b = t;              } if (a > c) {t = A;              A = C;              c = t;               } if (a > D) {t = A;               A = D;               d = t;   }              if (b > c) {t = b;               b = C;               c = t;               } if (b > D) {t = b;               b = D;               d = t;               } if (C > D) {t = C;               c = D;               d = t;        } System.out.println ("max=" + D);                Array method to solve int p[] = new INT[4];            for (int i = 0; i < 4; i++) {System.out.println ("Please enter" + (i + 1) + "number:");        P[i] = Scanner.nextint (); } for (int i = 0; i < 3; i++) {if (P[i] > p[i + 1]) {//Here you can also set a                Intermediate variable t to exchange p[i] = P[i] + p[i + 1];                P[i + 1] = P[i]-p[i + 1];            P[i] = P[i]-p[i-1]; }} System.out.println ("max=" + p[3]);//The largest is placed at the end of the array}