# Codeforces Round #1 C Ancient Berland Circus (computational geometry)

Source: Internet
Author: User

The idea of the problem is very good to think, divided into the following 4 steps:

1: Seek the radius of the circumscribed garden

2: Ask for three central angle

3: Find the greatest common divisor of three center angle

4: Greatest Common divisor is the largest regular polygon internal angle, to find the area can be.

But every step does not beg ah .... Sad ... When I think of the 3rd step, I even feel that I should ask for it in another way. To change the method. The geometry is too slag.

The code is as follows:

`#include <iostream> #include <string.h> #include <math.h> #include <queue> #include < algorithm> #include <stdlib.h> #include <map> #include <set> #include <stdio.h>using namespace std; #define LL __int64#define Pi ACOs ( -1.0) const int Mod=100000000;const int Inf=0x3f3f3f3f;const double eqs=0. 01;struct point{double x, y;} P;bool DMP (double x, double y) {return fabs (XY) <eqs;}    Double FGCD (double x, double y) {if (DMP (x,0)) return y;    if (DMP (y,0)) return x; Return FGCD (Y,fmod (x, y));} Double Dist (Point F1, point F2) {return sqrt ((f1.x-f2.x) * (f1.x-f2.x) + (F1.Y-F2.Y) * (F1.Y-F2.Y));}    int main () {double S, R, Ang, D, pp, angle;    int i;    for (i=0;i<3;i++) {scanf ("%lf%lf", &p[i].x,&p[i].y);    } for (i=0;i<3;i++) {d[i]=dist (p[i],p[(i+1)%3]);    } pp= (D+d+d)/2.0;    S=sqrt (pp* (pp-d) * (pp-d) * (pp-d));    r=d*d*d/(4*s);    Ang=acos (1-d*d/(2*r*r)); Ang=acos(1-d*d/(2*r*r));    ANG=2*PI-ANG-ANG;    ANGLE=FGCD (ang,ang);    ANGLE=FGCD (angle,ang);    printf ("%.6f\n", R*r*pi*sin (angle)/angle); return 0;}`

Codeforces Round #1 C Ancient Berland Circus (computational geometry)

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