Communication Algorithm 5: gain comparison of five encoding methods and matlab simulation, among which, matlab

Communication Algorithm 5: gain comparison of five encoding methods and matlab simulation, among which, matlab

1. convolution code gain performance and Error Rate

Channel environment: AWGN

SNR: 0: 0.1: 6

MATALB simulation architecture: Source bit + convolution code + BPSK + AWGN + Viterbi + BER

Note: convolution code, different R bit rates, and different constraints

2. Turbo gain performance and Error Rate

Channel environment: AWGN

SNR :-.

MATALB simulation architecture: Source bit + Turbo encoding + BPSK + AWGN + Turbo decoding + BER

Note: turbo decoding, different decoding algorithms, different intertwined lengths, and different iterations.

LTE standard turbo

3GPP standard turbo (DSP6455, TCP2, VCP2, also verified)

3. Gain performance and Error Rate

Channel environment: AWGN

SNR :-.

MATALB simulation architecture: Source bit/S + low-income ratio encoding + BPSK + AWGN + low-income ratio decoding + BER

(In the DVB-S2, CCSDS applications.

4. BCH/RS gain performance and bit error rate

Channel environment: AWGN

SNR :-.

MATALB simulation architecture: Source bit + BCH encoding + BPSK + AWGN + BCH decoding + BER

<For more information and the corresponding MATLAB code, contact qq: 1279682290>

How can I customize the encoding method when using genetic algorithm programming in matlab?

You are using the Genetic Algorithm Toolbox, right? Let's take a look at "MATLAB Genetic Algorithm Toolbox and application" Lei Yingjie, 2004 this book. You can find an electronic version online.
If the programming capability is strong, you are advised to write your own genetic algorithm to solve the problem. A lot of code can be found online.

Who will use matlab to implement the Harman coding algorithm?

Based on MATLAB

Function [h, l] = huffman (p)
If (length (find (p <0 ))~ = 0)
Error ('not a prob, negative component ');
End
If (abs (sum (p)-1)> 10e-10)
Error ('not a prob. vector, component do Not add to 1 ')
End
N = length (p );
Q = p;
M = zeros (n-1, n );
For I = 1: n-1
[Q, l] = sort (q );
M (I, :) = [l (1: n-I + 1), zeros (1, I-1)];
Q = [q (1) + q (2), q (3: n), 1];
End
For I = 1: n-1
C (I, :) = blanks (n * n );
End
C (n-1, n) = '0 ';
C (n-1, 2 * n) = '1 ';
For I = 2: n-1
C (n-I, 1: N-1) = c (n-I + 1, n * (find (m (n-I + 1, :) = 1 ))...
-(N-2): n * (find (m (n-I + 1, :) = 1 )));
C (n-I, n) = '0 ';
C (n-I, n + * N-1) = c (n-I, 1: N-1 );
C (n-I, 2 * n) = '1 ';
For j = 1: I-1
C (n-I, (j + 1) * n + 1 :( j + 2) * n) = c (n-I + 1 ,...
N * (find (m (n-I + 1, :) = j + 1)-1) + 1: n * find (m (n-I + 1, :) = j + 1 ));
End
End

For I = 1: n
H (I, 1: n) = c (1, n * (find (m (1, :) = I)-1) + 1: find (m (1, :) = I) * n );
Ll (I) = length (find (abs (h (I ,:))~ = 32 ));
End
L = sum (p. * ll );