Compiler practice three syntax parser for arithmetic expressions

Part of the code from MOOC

#include <ctype.h> #include <stdio.h> #include <stdlib.h>void parse_f (); void parse_t (); void Parse_e ( ); void error (char *want, Char got); int I;char *str = 0;void error (char *want, Char got) {fprintf (stderr, "compling thi  S expression:\n%s\n ", str);  int j = i;  while (j--) fprintf (stderr, "");  fprintf (stderr, "^\n"); fprintf (stderr, "Syntax error at position:%d\n" "\texpecting:%s\n" "\tbut Got:%c\n", I  , want, got);  Exit (0); return;}  void Parse_f () {char c = str[i];    if (IsDigit (c)) {i++;  Return    } if (c== ' (') {i++;    Parse_e ();    c = Str[i];      if (c== ') ') {i++;    Return    } error ("\ ') \ '", c);  Return  } error ("\ ' 0-9\ ' or \ ' (\ '", c); return;}  void parse_t () {parse_f ();  char C = str[i];    while (c== ' * ' | | c = = '/') {i++;    Parse_f ();  c = Str[i]; } return;  void Parse_e () {parse_t ();  char C = str[i];    while (c== ' + ' | | c = = '-') {i++;    parse_t ();  c = Str[i]; } return; void PArse (char *e) {str = e;  i = 0;  Parse_e ();  if (str[i]== ') return;  Error ("\ ' +\ ' or ' \\0\ '", Str[i]); return;} Your job://Add Some code into the function parse_e () and//parse_t to P Arse "-" and "/" correctly.//when you finish your tasks, NO error message//should be generated.//enjoy! :-P int Main (char argc, char **argv) {//There is the following rules on an expression://1.  Every expression is represented as a string; 2.  integers is non-negative; 3.  Integers is between 0-9.  Char *e;  E = "(2)";  Parse (e);  E = "(3+4*5))";  Parse (e);  E = "(8-2) * *";  Parse (e);  E = "(8-2)/3";    Parse (e); return 0;}

with June

Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced.

Compiler practice three syntax parser for arithmetic expressions