Complete the Pattern #6-odd Ladder

Complete the Pattern #6-odd laddertask:

You has to write a function pattern which creates the following pattern (see examples) up to the desired number of rows.

• If the Argument is 0 or a negative integers then it should return "" i.e. empty string.

• If any even number was passed as argument then the pattern should last upto the largest odd number which is smaller than th E passed even number.

Examples:

Pattern (9):

1333555557777777999999999

Pattern (6):

133355555

Note: There are no spaces in the pattern

Hint: Use \n in string to jump to next line

usingSystem;usingSystem.Collections.Generic;usingSystem.Linq; Public Static classkata{ Public Static stringOddladder (intN) {stringresult =string.                           Empty; List<int> list =Newlist<int>();  for(inti =1; I <= N; i = i +2) {list.                ADD (i); } result=string. Join ("\ n", list. Select (item =Selector (item))); returnresult; }         Public Static stringSelector (intNumber ) {             stringstr =string.            Empty;  for(inti =0; I < number; i++) {str= str +Number .            ToString (); }            returnstr; }}

Select in LINQ

public static ienumerable<tresult> Select<tsource, tresult> (this ienumerable<tsource> source, Func<tsource, tresult> selector);

Func<tsource, tresult> generic delegate
Public delegate TResult Func<in T, out tresult> (t Arg)

Other people's Solution:

usingSystem;usingSystem.Linq; Public Static classkata{ Public Static stringOddladder (intN) {if(N <=0)returnString.Empty; varOddnumbers = Enumerable.range (1, N). Where (i = i%2==1); varlines = Oddnumbers.select (i = String.Join ("", Enumerable.repeat (i.ToString (), i)); returnstring.join (Environment.NewLine, lines); }}

Complete the Pattern #6-odd Ladder