Computer Basics: decimal/hexadecimal/binary

Define the following variables. Assume that int occupies 2 bytes, long occupies 4 bytes, and char occupies 1 byte!

 

Int I = 0x1234; // occupies two bytes <br/> long l = 0x12345678; // occupies four bytes <br/> char C = 0x12; // occupies one byte

 

Why is the hexadecimal value of the int type four digits? Step by step!

 

First, what is the concept of converting int type to binary type?

1 int byte is converted to 8 binary bits, for example, int A = 100; then the binary form of A is 25 + 24 + 22; that is, 0011 0100;

Converting int type to binary type is 1 to 8!

 

Next, let's look at the conversion of binary and hexadecimal:

You probably guessed it. Yes, that's right! Four Binary values are converted to one hexadecimal value. The values are: 0011 0100 ---> 0x34.

 

Therefore, the conversion between decimal and hexadecimal is like this. One byte is changed to two digits, and the two byte is changed to four digits...

Therefore, defined as long l = 0x12345678 actually occupies 8/2 = 4 bytes!

 

Postscript: It's all about university skipping classes !!!