# Convert RMB to uppercase

Source: Internet
Author: User
`/*** Convert RMB into uppercase ** @ Param value * @ return string */public static string hangetobig (double value) {char [] hunit = {'pick ', 'hangzhou', 'hangzhou'}; // The position in the segment indicates char [] vunit = {'wan', 'yi '}; // The segment name indicates char [] digit = {'0', 'yi', 'er', 'san', 'siz', 'wu', 'lu ', 'handler', 'handler', 'handler'}; // number indicates long midval = (long) (value * 100); // converts it to an integer string valstr = string. valueof (midval); // convert it to string head = valstr. substring (0, valstr. length () -2); // take the integer part string rail = valstr. substring (valstr. length ()-2); // returns the string prefix = "" in the decimal part; // returns the string suffix = ""; // result of converting the fractional part // process the number of digits after the decimal point if (rail. equals ("00") {// If the fractional part is 0 suffix = "integer";} else {suffix = digit [rail. charat (0)-'0'] + "" + digit [rail. charat (1)-'0'] + "points"; // otherwise, convert the corner points} // process the number before the decimal point char [] chdig = head. tochararray (); // converts the integer part to the character array char zero = '0'; // flag '0 'Indicates the occurrence of 0 byte zerosernum = 0; // the number of consecutive occurrences of 0 for (INT I = 0; I <chdig. length; I ++) {// cyclically process each number int idx = (chdig. length-I-1) % 4; // get the position in the segment int vidx = (chdig. length-I-1)/4; // take the segment position if (chdig [I] = '0') {// if the current character is 0 zerosernum ++; // If (zero = '0') {// flag zero = digit [0];} else if (idx = 0 & vidx> 0 & zerosernum <4) {prefix + = vunit [vidx-1]; zero = '0';} continue;} zero Sernum = 0; // zero if (zero! = '0') {// if the flag is not 0, add the prefix + = zero; zero = '0 ';} prefix + = digit [chdig [I]-'0']; // convert this number to If (idx> 0) prefix + = hunit [idx-1]; if (idx = 0 & vidx> 0) {prefix + = vunit [vidx-1]; // The end position of the segment should contain a segment name, million} If (prefix. length ()> 0) prefix + = 'circle '; // If the integer part exists, return prefix + suffix; // return the correct representation}`
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