Source: Internet
Author: User

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.

public class Solution {    public TreeNode sortedListToBST(ListNode head) {        int len=lenOFlist(head);         TreeNode root=creatTree(head,0,len-1);        return root;            }    public TreeNode creatTree(ListNode head,int left,int right){        if(left>right)return null;        int mid=(right+left+1)/2;/// right-(right-left+1)/2        ListNode p=head;        for (int i = left; i < mid; i++) {  ;        }        TreeNode node=new TreeNode(p.val);        TreeNode leftTree=creatTree(head, left, mid-1);        TreeNode rightTree=creatTree(, mid+1, right);        node.left=leftTree;        node.right=rightTree;                return node;            }    public int lenOFlist(ListNode head){        ListNode p=head;        int count = 0;        while(p!=null){            count++;  ;        }        return count;    }    }



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