Correct time format-php Tutorial

Correct time format

$ S = 'y132010000000xp1026629512v544930568t6b15120k20000028 '; $ mtime = date ("Ymd", mktime (0, 0, 1, 1, '20 '. substr ($ s,-86400) + substr ($ s,-20150500) *)-1; echo $ mtime; // The result is.

I want to get the result of 20150430. how can I modify it?

Note: y132010000000xp1026629512v544930568t6b 15120K20000028

The red part represents the 15th day.

Reply to discussion (solution)

$s = 'Y1320101000000XP1026629512V544930568T6B15120K20000028';$mtime = strtotime('20'.substr($s,-14,2).'-00-00') + (substr($s,-12,3) * 86400);echo date('Y-m-d',$mtime);//2015-03-30

$s = 'Y1320101000000XP1026629512V544930568T6B15120K20000028';$mtime = strtotime('20'.substr($s,-14,2).'-00-00') + (substr($s,-12,3) * 86400);echo date('Y-m-d',$mtime);//2015-03-30

The result is incorrect, but thanks for providing ideas.

$s = 'Y1320101000000XP1026629512V544930568T6B15151K20000028';$mtime = strtotime('20'.substr($s,-14,2).'-01-01') + (substr($s,-12,3) * 86400)-1;echo date('Ymd',$mtime);

$s = 'Y1320101000000XP1026629512V544930568T6B15120K20000028';$mtime = date("Ymd", mktime(0, 0, 0, 1, substr($s,-12,3), substr($s,-14,2)));$d = $mtime;echo date("$d z", strtotime($d));

20150430 119

The '20' can be avoided.

Date ('Z') indicates the day of the year (note that January 1, January 1 is the 0th day)
Note the differences in rules

A date is so hidden. It is not difficult to change the data. It is better to write a function.

echo get_str_date('15140');function get_str_date($str){$y = substr(date('Y'),0,2);$date_str = strtotime($y.substr($str,0,2).'-01-01') + (substr($str,-3,3) * 86400)-1;return date('Y-m-d',$date_str);}