Cross linked list codeforces Round #367 E working routine

Source: Internet
Author: User

1 //Cross linked list codeforces Round #367 E working routine2 //Test instructions: give you a matrix, Q-Ask, two sub-matrices per exchange, ask the final matrix3 //idea: violence must not. We can create a cross-linked list of each element, record the right and bottom elements, and subscript each element (starting at 0), each asking for only four points to be exchanged. 4 //to establish a matrix (n+1) * (m+1)5 6#include <bits/stdc++.h>7 using namespacestd;8 #defineLL Long Long9 Const DoubleINF =123456789012345.0;Ten ConstLL MOD =100000000LL; One Const intN =1010*1010; A #defineCLC (A, B) memset (A,b,sizeof (a)) - Const DoubleEPS = 1e-7; - voidFre () {freopen ("In.txt","R", stdin);} the voidFreout () {freopen ("OUT.txt","W", stdout);} -InlineintRead () {intx=0, f=1;CharCh=getchar (); while(ch>'9'|| ch<'0') {if(ch=='-') f=-1; Ch=getchar ();} while(ch>='0'&&ch<='9') {x=x*Ten+ch-'0'; Ch=getchar ();}returnx*F;} -  - intn,m,q; + structnode{ -     intv,r,d; + }a[n]; A  at intChgintYintx) { -     returny* (m+1)+x; - } -  - intMain () { -scanf"%d%d%d",&n,&m,&q); in      for(intI=1; i<=n;i++){ -          for(intj=1; j<=m;j++){ toscanf"%d",&A[chg (i,j)].v); +         } -     } the  *      for(intI=0; i<=n;i++){ $          for(intj=0; j<=m;j++){Panax NotoginsengA[chg (i,j)].r=chg (i,j+1); -A[chg (i,j)].d=chg (i+1, j); the         } +     } A      while(q--){ the         intx1,y1,x2,y2,h,w; +scanf"%d%d%d%d%d%d",&y1,&x1,&y2,&x2,&h,&W); -         intp1=0, p2=0; $          for(intI=1; i<y1;i++) p1=a[p1].d; $          for(intI=1; i<x1;i++) p1=A[P1].R; -          for(intI=1; i<y2;i++) p2=a[p2].d; -          for(intI=1; i<x2;i++) p2=A[P2].R; the         intt1=P1; -         intT2=P2;Wuyi          for(intI=1; i<=h;i++){ thet1=a[t1].d; -T2=a[t2].d; Wu swap (A[T1].R,A[T2].R); -         } About          for(intI=1; i<=w;i++){ $t1=A[T1].R; -T2=A[T2].R; - swap (A[T1].D,A[T2].D); -         } AT1=p1,t2=P2; +          for(intI=1; i<=w;i++){ thet1=A[T1].R; -T2=A[T2].R; $ swap (A[T1].D,A[T2].D); the         } the          for(intI=1; i<=h;i++){ thet1=a[t1].d; theT2=a[t2].d; - swap (A[T1].R,A[T2].R); in         } the     } the     intp=0; About      for(intI=1; i<=n;i++){ thep=a[p].d; the         intq=p; the          for(intj=1; j<=m;j++){ +q=A[Q].R; -printf"%d", A[Q].V); the         }Bayiprintf"\ n"); the     } the     return 0; -}

Cross linked list codeforces Round #367 E working routine

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.