This will not cause stack explosion, but the efficiency is very low. The time complexity of O (N ^ 2) needs to be optimized.
#include <stdio.h>#define N 10int q[N+1] = {0};int cnt = 0;void print_q() { int i; for (i=0; i<N; i++) printf("%d ", q[i]); printf("\n"); return;}int can_put(int m, int n) { int i,j; //row is ok //colume for (i=0; i<m; i++) { if (q[i] == n) return 0; } //left-up for (i=m-1,j=n-1; i>=0 && j>=0; i--,j--) { if (q[i] == j) return 0; } //right-up for (i=m-1,j=n+1; i>=0 && j<N; i--,j++) { if (q[i] == j) return 0; } return 1;}void next_qn() { int i=0; while (i <= N) { if (q[i] < N-1) { q[i] +=1; break; } q[i] = 0; i++; } return;}int main(int argc, char* argv[]) { while (q[N] == 0) { int i; for (i=0; i<N; i++) { if (!can_put(i, q[i])) break; } if (i == N) { cnt++; print_q(); } next_qn(); } printf("CNT: %d\n", cnt); return 0;}
Cycle 8 queens