Daily use of the Python datetime module

Daily use of the Python datetime module

[10:52:43] [Email protected]| ~]# python

Python 2.7.12 (Default, June 27 2017, 11:19:01)

[GCC 4.8.5 20150623 (Red Hat 4.8.5-4)] on linux2

Type "Help", "copyright", "credits" or "license" for more information.

>>> Import datetime

# Get current time, output in string format

>>> datetime.datetime.now () # Output current time, DateTime format

Datetime.datetime (2017, 7, 31, 10, 53, 8, 430324)

>>> Print type (Datetime.datetime.now ())

<type ' Datetime.datetime ' >

>>> Datetime.datetime.now (). Strftime ("%F%T") # DateTime format converted to str format

' 2017-07-31 10:53:46 '

>>> Print type (Datetime.datetime.now (). Strftime ("%F%T"))

<type ' str ' >

# Calculate Time Difference

>>> start = Datetime.datetime.now ()

>>> end = Datetime.datetime.now ()

>>> print Start, type (start)

2017-07-31 10:58:36.875319 <type ' datetime.datetime ' >

>>> print end, type (end)

2017-07-31 10:58:51.778787 <type ' datetime.datetime ' >

>>> time_seconds = (end-start). Seconds # How many seconds difference

>>> print Time_seconds, type (time_seconds)

<type ' int ' >

>>> time_microseconds = (end-start). Microseconds # How many microseconds difference

>>> print Time_microseconds, type (time_microseconds)

903468 <type ' int ' >

>>> time_days = (end-start). Days # How long is the difference?

>>> print time_days, type (time_days)

0 <type ' int ' >

>>> delta_time = float (str (time_days*86400 + time_seconds) + "." + str (time_microseconds)) # Calculate the difference in number of seconds (three parts need to be added)

>>> print Delta_time, type (delta_time)

14.903468 <type ' float ' >

# Convert the time of the STR format to the datetime format

>>> time_string = "2012-02-02 22:22:22"

>>> print type (time_string)

<type ' str ' >

>>> time_datetime = Datetime.datetime.strptime (time_string, "%y-%m-%d%h:%m:%s")

>>> print Time_datetime, type (time_datetime)

2012-02-02 22:22:22 <type ' datetime.datetime ' >

# Calculates a time difference of two times

>>> T1 = "2012-02-02 22:22:22"

>>> t2 = "2012-02-28 11:11:11"

>>> t1_datetime = datetime.datetime.strptime (T1, "%y-%m-%d%h:%m:%s")

>>> t2_datetime = datetime.datetime.strptime (T2, "%y-%m-%d%h:%m:%s")

>>> T2_datetime

Datetime.datetime (2012, 2, 28, 11, 11, 11)

>>> T1_datetime

Datetime.datetime (2012, 2, 2, 22, 22, 22)

>>> print (t2_datetime-t1_datetime). Days

25

>>> print (t2_datetime-t1_datetime). seconds

46129

>>> delta_t = delta_days*86400 + delta_seconds # Calculate the difference in number of seconds

>>> print delta_t, type (delta_t)

2206129 <type ' int ' >

Attention:

T2 time part converted to seconds: 40271

T1 time part converted to seconds: 80542

So the number of seconds to subtract, you need to automatically borrow a day from the days, that is 86400+40271-80542=46219

And the days subtract into 28-1-2=25

Daily use of the Python datetime module