Data structures and algorithms-decomposing sequences into separate variables

Source: Internet
Author: User

① problem: If there is a tuple or sequence containing n multiple elements, now you want to break it down into n separate variables.

1 L = (4, 5)2 x, y = l
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② Advanced article:

data = ['sb' ' big hammer ', (2018, 6, 2  = dataa='sb'b=' big hammer '  C=51Date= (2018, 6, 2)

data = ['sb' ' big hammer ', (2018, 6, 2  == 2018= 6= 2
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So then the question comes, this is to know the list of how much of the situation to achieve, if the unknown? that will use the * expression to decompose the iterated object.

* syntax is useful when iterating over a tuple sequence of an edge length, with an example:

Records = [    ('Foo', 1, 2),    ('Bar','Hi'),    ('Foo', 3, 4),]defDo_foo (x, y):Print('Foo', x, y)defDo_bar (s):Print('Bar', s) forTag, *argsinchRecords:ifTag = ='Foo': Do_foo (*args)elifTag = ='Bar': Do_bar (*args)
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Data structures and algorithms-decomposing sequences into separate variables

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