Django uploads images, uses PIL to create thumbnails, and saves them to the storage of sea,

Django uploads images, uses PIL to create thumbnails, and saves them to the storage of sea,

Upload Image Parsing:

The SAES settings are as follows:

Process uploaded files

Add the following configuration in setttings. py.

# Modify the maximum size that files can be stored in the memory during upload to 10mFILE_UPLOAD_MAX_MEMORY_SIZE = 10485760 # the local file system of sae is read-only, and change django's file storage backend to StorageDEFAULT_FILE_STORAGE = 'sae. ext. django. storage. backend. store' # Use media this bucketSTORAGE_BUCKET_NAME = 'Media '# ref: https://docs.djangoproject.com/en/dev/topics/files/

 

There are two situations:

• An image is a field in the database, for example:

class Picture(models.Model):    """docstring for Picture"""    user = models.ForeignKey(Customer)    image = ThumbnailImageField(upload_to='goods_photo')

Then you just need to write it in the view function, at this time, SAE can automatically help you upload images to the goods_photo folder under the media domain in storage (remember to activate storage on SAE and create a file named you in settings. the STORAGE_BUCKET_NAME set by py, and create a folder named the value of upload_to under this domain)

def upload_photo(request):    f = request.FILES['upload_file']    name=copy.copy(f.name)    p = Picture()    p.image = f    user_id = request.POST['user_id']    user = Customer.objects.get(pk=user_id)    p.user = user    p.save()

• Directly upload images to storage

Refer to the storage api documentation of sea.

Now, I want to upload an image and generate a thumbnail. The image is a field in the database, the thumbnail accesses the thumbnail through a custom attribute thumb_url of the database to customize a ThumbnailImageField. The reference code is as follows:

# ThumbnailImageField.pyfrom django.db.models.fields.files import ImageField,ImageFieldFilefrom PIL import Imagedef _add_thumb(s):    parts = s.split(".")    parts.insert(-1,"thumb")    if parts[-1].lower() not in ['jpeg','jpg']:        parts[-1]='jpg'    return ".".join(parts)class ThumbnailImageFieldFile(ImageFieldFile):    def _get_thumb_url(self):        return _add_thumb(self.url)    thumb_url = property(_get_thumb_url)    def save(self,name,content,save=True):        super(ThumbnailImageFieldFile, self).save(name,content,save)    def delete(self,save=True):        super(ThumbnailImageFieldFile, self).delete(save)        class ThumbnailImageField(ImageField):    """docstring for ThumbnailImageField"""    attr_class = ThumbnailImageFieldFile    def __init__(self,*args,**kwargs):        super(ThumbnailImageField, self).__init__(*args,**kwargs)

View functions are as follows:

def upload_photo(request):    f = request.FILES['upload_file']    name=copy.copy(f.name)    p = Picture()    p.image = f    user_id = request.POST['user_id']    user = Customer.objects.get(pk=user_id)    p.user = user    p.save()    c = sae.storage.Connection()    bucket = c.get_bucket('media')    obj = bucket.get_object_contents("goods_photo/"+name)    image = Image.open(StringIO(obj))    image.thumbnail((90,90),Image.ANTIALIAS)    imgOut = StringIO()    image.save(imgOut, 'jpeg')    img_data = imgOut.getvalue()    bucket.put_object('goods_photo/'+_add_thumb(name), img_data)    imgOut.close()

View function details:

P. save () will consume the request. FILES ['upload _ file']. Therefore, we recommend that you first save the file to storage and then extract the image from storage for processing.
Name = copy. copy (f. name), the reason for using the shortest copy is that p. save () will consume the request. FILES ['upload _ file'], name = f. you do not know what the name is. You can also use deepcopy, but it is not necessary because name is a string.
Bucket. get_object_contents ("goods_photo/" + name), storage of sea does not support direct directory structure, but directory structure can be simulated by file name