Linux under How many "-" will be printed:
| 12345678 |
int main ( void &NBSP;&NBSP; int i; &NBSP;&NBSP; for (i=0;i<4;i++) { &NBSP;&NBSP; fork (); &NBSP;&NBSP; printf ( &NBSP; } &NBSP; return 0; |
When I=0, the main process and the child processes it creates are printed '-', print 2 I=1, the previous two processes print '-', each process creates a new subprocess, a total of 4 '-' i=2, the previous four processes print '-', and create a new sub-process, so the total printing of 8 '-' i=3, The previous 8 processes print '-', and create new sub-processes, so print a total of 16 '-' to sum up, the total print 2+4+8+16=30 each call fork () function, the parent thread and the created child threads are executed from fork (), means that the parent and child threads will perform the printf once, respectively. So the 1-time fork () call corresponds to 2 printf () calls corresponding to the creation of 1 child threads i = 4 o'clock, altogether creating a 2^4-1 child thread, that is, 15 fork () calls, so the call is 30 times printfhttps://www.nowcoder.co m/questionterminal/9b52b1a86ae64daab81f609f3a86c02f
Each time the fork () function is called, both the parent thread and the created child thread are executed from the fork ()
