Enter a line of characters to count how many words there are, separated by spaces between the words

Problem Description:

Enter a line of characters to count how many words there are, separated by spaces between the words

Problem Solving Ideas:

To determine whether the word appears, you can use the appearance of the space to judge (a continuous number of spaces to make a), if the current character is a space, indicating that Word does not appear, the current word printable space, the previous character is a space to indicate that the new word appears, count++, before the character is a space, with the status flag word to mark

The code is as follows:

#include <stdio.h>   //printf#include<string.h>  //gets#include<stdlib.h>  //system# Define Maxlenth 1000//character array maximum capacity int main () {System ("title count the number of 9");//Set CMD window title system ("Mode con cols=100 line S=100 ");//Set window width and height system (" color 0A ");                   Set Curtain and font color char string[maxlenth];//a character char *ch = String that holds the terminal input;    Point to the array int count = 0;        Count the number of words int word = 0;         The status flag bit, the new word appears (the current word printable space, before the character is a space) word=1, otherwise word = 0printf ("Please input the charactors you want to count the words:\n"); String), for (; *ch! = ' ++ch ') {if (*ch = = ')    //The current character is ' space ', indicating that the new word does not appear {word = 0;} else if (Word = = 0)//(the current character printable space, preceded by a space) Word=1{count++;word = 1;}} printf ("There is%d words\n", count); return 0;}

It can also be used without pointers, with the following code:

#include <stdio.h>       //printf#include<stdlib.h>      //system#include<string.h>      // Getsint Main () {System ("mode con cols=100 lines=100"); System ("Color 0A"); Char string[100000];//holds a character int num = 0;        Count the number of words int word = 0;       The sign of whether the word appears, 0: The new word does not appear, 1: The new word appears int i;printf ("Please input the charactors so want to Count words:\n"); gets (string); 
   //from the terminal enter a character for which you want to count the number of words for (i=0;string[i]! = ' 0{word '; ++i) {if (string[i] = =)//The current character is a space, indicating that the new word does not appear word = = 0;} else if (Word = = 0)  //The current character is not a space and the previous character is a space, indicating that the new word appears {word = 1;num++;}} printf ("There is%d words in the charactors you put \ n", num); system ("pause"); return 0;}

Enter a line of characters to count how many words there are, separated by spaces between the words