Enter N to print a matrix of n X N on the screen, using dynamic memory to allocate int * * num

Input 3:

Output:

1 2 3

8 9 4

7 6 5

The code is as follows:

#include <iostream>
#include <math.h>
using namespace std;
int main ()
{
	int N;
	int i,j;
	int count,m;
	int **num;
	cout<< "Please enter the value of N:";
	cin>>n;
	num= (int * *) malloc (sizeof (int *) *n);
	for (i=0;i<n;i++)
	{		
		num[i]= (int *) malloc (sizeof (int) *n);
	}
	Count=1;
	M=1;
	for (i=0;i<n;i++)//First row
	{
		num[0][i]=m++;
	}
	for (j=n-1;j>=n/2;j--)
	{for
		(i=count;i<=j;i++)//Last column
		{
			num[i][j]=m++;
		}
		for (i=j;i>=count;i--)//The bottom line
		{
			num[j][i-1]=m++;
		}
		for (i=j-1;i>=count;i--)//Leftmost column
		{
			num[i][count-1]=m++;
		}
		for (i=count;i<j;i++)//above the second row
		{
			num[count][i]=m++;
		}
		count++;
	}
	for (i=0;i<n;i++)
	{
		for (j=0;j<n;j++)
		{
			printf ("%3d  ", Num[i][j]);
		}
		cout<<endl;
	}
	return 0;
}