Error generating Swagger server (Python Flask) from Swagger editor, swaggerflask

Error generating Swagger server (Python Flask) from Swagger editor, swaggerflask

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Http://stackoverflow.com/questions/36416679/error-generating-swagger-server-python-flask-from-swagger-editor   I 've used the Swagger Editor to manually generate my Swagger spec file and generated the files for a Python Flask server. Following the readme I installed connexion, but when I runpython app.pyI get the error: ValueError: need more than 1 value to unpack. Any ideas? Full stack trace below: No handlers could be found for logger "connexion.api"Traceback (most recent call last): File "app.py", line 5, in <module> app.add_api('swagger.yaml') File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/app.py", line 144, in add_api debug=self.debug) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/api.py", line 127, in __init__ self.add_paths() File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/api.py", line 198, in add_paths six.reraise(*sys.exc_info()) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/api.py", line 187, in add_paths self.add_operation(method, path, endpoint, path_parameters) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/api.py", line 160, in add_operation resolver=self.resolver) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/operation.py", line 168, in __init__ resolution = resolver.resolve(self) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/resolver.py", line 50, in resolve return Resolution(self.resolve_function_from_operation_id(operation_id), operation_id) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/resolver.py", line 71, in resolve_function_from_operation_id return self.function_resolver(operation_id) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/connexion/utils.py", line 106, in get_function_from_name module_name, attr_path1 = module_name.rsplit('.', 1)ValueError: need more than 1 value to unpack Python flask swagger Share | improve this question Asked Apr 5 at :36 tw1742 117211

1 Please open a ticket via github.com/swagger-api/swagger-codegen/issues for tracking.-wing328 Apr 6 at 4: 45 Add a comment |

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I ran into this as well. from what I see, the generated code from Swagger seems to assume you're using Python 3. while connexion supports both Python 2.7 & 3.4 +, it does need__init__.pyFile in the generatedpython-flask-server/Base directory as well as insidecontrollers/Subdirectory to work for Python 2.7 (Implicit Namespace Packages were introduced in Python 3.3 ). if you create those 2 empty files after generating the code, things shocould work. if the Swagger generator wants to support Python 2.7 (since connexion allows for it), it wocould just need to provide those files as well.