Evaluate the problem of "No duplicated plural", which is larger than the specified number

Given any positive integer, the minimum number is greater than this number. The meaning of the number is that two adjacent digits are different. For example, 1101 is the number of duplicates, and 1201 is not a complex number.

 

#include <stdio.h>#include <stdlib.h>#include <errno.h>#define NUMBER_STR_MAX_LENGTH (128)unsigned find(unsigned);int main(void){    unsigned num = 0;    printf("Please input Unsigned Number : ");    if (scanf("%u", &num) != 1) {        perror("input error!");        return 1;    }    printf("%u\n", find(num));    return 0;    }void str_reverse(unsigned char *str,unsigned length){    unsigned char *prv = NULL;    unsigned char *cur = NULL;    unsigned char swap = '\0';    for (prv = str, cur = str + (length-1)            ; prv < cur; ++prv, --cur){        swap = *prv;        *prv = *cur;        *cur = swap;    }}unsigned find(unsigned number){    unsigned char number_str[NUMBER_STR_MAX_LENGTH] = {'\0'};    unsigned char *prv = NULL;    unsigned char *cur = NULL;    unsigned char *finded = NULL;    unsigned int number_length = 0;    unsigned int result = 0;      int carry = 0;    ++number;    number_length = sprintf(number_str, "%u", number);    str_reverse(number_str, number_length);    for (cur = number_str + (number_length-1), finded = number_str            ; cur > finded - 1 ; --cur ){            if (prv != NULL && *prv == *cur){            finded = cur;            carry = 1;            do {                *cur += carry;                carry = (*cur - '0') / 10u;                *cur = (*cur-'0') % 10u + '0';                ++cur;            } while (carry != 0 && cur < (number_str + number_length));            if (carry > 0){                *cur = '0' + carry ;                ++number_length;            }        }        prv = cur;    }    /* set reset as 010101 */    for (carry = 0; cur > number_str - 1; --cur){        *cur = carry + '0';        carry ^= 1u;    }    str_reverse(number_str, number_length);    sscanf(number_str,"%u",&result);    return result;}

 

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