Execution of return statement in try-catch-finally

Will it execute finally after the catch is return??
In Java, yes.
It is worth noting, however, that in the method where try-catch-finally is present, there are 4 locations where return can occur, in try, in catch, finally, after finally (statement block outside try-catch-finally).
In the case of return in all 4 positions (in fact it should be impossible, if there is a return in the previous 3 positions, then the return of the last position becomes unreachable code, the compilation will not pass), The return that will eventually be executed should be the return in the finally. That is, the return in the finally will overwrite the return from the other position.
However, when return is not present in Finally, and return is present in a catch, the statement in finally has an effect on the value of return in the catch, which is a bit complicated. See the following example:

int ret = 0;try{throw new Exception ();} catch (Exception e) {ret = 1; return ret;} finally{ret = 2;//return ret;} return ret;

There is no return in Finally, but the RET to return in the catch is assigned a value of 2. So what is the last value returned?
is 1. Why?
From debugging you can know that the assignment statement in finally is executed, and the next statement after executing this finally statement is the return in the catch, so why is 1 returned?
Looking at Java Language Specification 3.0, there seems to be no description of the situation.
In conjunction with some related articles on the web, it can only be inferred that, in this case (there is no return in the return,finally in the catch), the value of return has been determined before the finally execution.
Another notable note is that the last return (located outside of Try-catch-finally) is not executed.

Execution of return statement in try-catch-finally