Find consecutive numbers in the Python list (learned by netizens)

#-*-Coding:utf-8-*-

# python:2.x

__author__ = ' Administrator '

#学习这个要求的: http://wsky.org/archives/162.html

Import Sys

From itertools Import *

From operator Import *

Def parse (f):

d={}

For line in open (F, ' R '):

_line=line.split ()

D.setdefault (_line[0],[]). Append (_line[1])

For key in D.keys ():

data=sorted (Map (Lambda X:int (x[1:]), D[key]))

Sys.stdout.write (key+ ")

For K,g in GroupBy (Enumerate (data), Lambda (i,x): i-x):

Ret=map (Itemgetter (1), g)

If Len (ret) >1:

Sys.stdout.write (' s%d-%d '% (Ret[0],ret[-1]))

Elif Len (ret) ==1:

Sys.stdout.write (str (' s%s ')% (ret[0]+ ', '))

Sys.stdout.write (' \ n ')

If __name__== ' __main__ ':

F=SYS.ARGV[1]

Parse (f)

Find consecutive numbers in the Python list (learned by netizens)