Find the number within 100 that can be divisible by 7, display 7 per line, and then wrap the display

1. The script is as follows

#!/bin/bash

#初始化一个中间变量m

M=1

For ((i=1;i<=100;i++))

Do

#设置中间变量temp1的值

Let "temp1=i%7"

If ["$temp 1"-ne 0]; Then

Continue

Fi

#输入结果

Echo-n "$i"

#设置中间变量temp2的值, this value is used for line wrapping

Let "temp2=m%7"

#每行显示7个数

If ["$temp 2"-eq 0]; Then

echo ""

Fi

Let "m++"

Done

2. Output results

7 14 21 28 35 42 49

56 63 70 77 84 91 98

This article is from the "Never Stop" blog, please be sure to keep this source http://wjcaiyf.blog.51cto.com/7105309/1681478

Find the number within 100 that can be divisible by 7, display 7 per line, and then wrap the display