Find the number within 100 that is divisible by 7, each row shows 7, and then line-break displays

#!/bin/bash#  Initializes an intermediate variable mm=1for  ((i=1;i<=100;i++)) do         #  set the value of the intermediate variable temp1         let  "temp1=i%7"          if [  "$temp 1"  -ne 0 ]; then                 continue         fi        #  Input Results           echo -n  "$i  "          #  sets the value of the intermediate variable TEMP2, which is used for line wrapping         let  temp2=m%7          #  Show 7 numbers per row         if  [  "$temp 2"  -eq 0 ]; then                 echo  " "         fi         let  "m++"  done

The result is entered as:

7 14 21 28 35 42 49

56 63 70 77 84 91 98

This article is from the "Never Stop" blog, please be sure to keep this source http://wjcaiyf.blog.51cto.com/7105309/1690836

Find the number within 100 that is divisible by 7, each row shows 7, and then line-break displays