Title Description
Description
Given nn non-negative integers, please find the least non-negative integer This doesn ' t occur in the Nn Numbers.
Input
The first line was an integer T, representing the number of test cases. (T≤10)
The first line of all test case was an integer n (n≤2?10?^5??).
The second line of all test case is nn non-negativeintegers a? i?? (a? i?? <2?^31??).
Output
For each test case, output a linewith the answer.
Input sample
2
4
4 0 1 3
2
1 1
Output sample
2
0
Analysis: Violence in the range of numbers given, violence search is not not, but certainly will time out, online there are many solutions to the array elements are not duplicated, reference value is not very large, and then I think of a method, need to sort, then from the beginning, need to record the repetition number of repeated numbers, Based on the relationship between the subscript and the number of repetitions of the array, the solution is obtained. Time complexity O (n), Spatial complexity O (1)
Code:
1#include <algorithm>2#include <iostream>3#include <string>4#include <vector>5 using namespacestd;6 intMain ()7 {8 intN;9CIN >>N;Ten //Use the GCC compiler when playing a game, and be sure to place two > between them to avoid miscalculation Onevector<vector<int> > V (1001,vector<int> (200001, Int_max)); Avector<int> Len (1001); - for(inti =0; I < n; i++) - { the //int m; -CIN >>Len[i]; - for(intj =0; J < Len[i]; J + +) -CIN >>V[i][j]; + } - for(inti =0; I < n; i++) + { A intres =0; at intRepnum =0; - sort (V[i].begin (), V[i].end ()); - if(v[i][0] >0) - { -cout <<0<<Endl; - Continue; in } - Else to { + intj =1; - for(; J < Len[i]; J + +) the { * if(V[i][j] = = V[i][j-1]) $ {Panax Notoginsengrepnum++; - Continue; the } + if(V[i][j]! = J-repnum) A { thecout << J-repnum <<Endl; + Break; - } $ } $ if(J = =Len[i]) -cout << Len[i] <<Endl; - } the } -System"Pause");Wuyi return 0;
Finds the smallest positive integer that does not appear in an array (the array element can be duplicated)