223. Rectangle Area

Source: Internet
Author: User

    /** 223. Rectangle areas * 12.12 by Mingyang * Large area minus small area * Here we test instructions do not understand wrong oh, here is to find all the place is cover, not only by the two overlap cover place * so we need To find two of the sum of the area minus the middle repeat two times the small area*/     Public intComputearea (intAintBintCintDintEintFintG,intH) {intMinu = 0; if(E >= C | | G <= A | | F >= D | | H <=B) Minu= 0; ElseMinu= (Math.min (G, C)-Math.max (A, E))* (Math.min (D, H)-Math.max (F, B)); return(c-a) * (d-b) + (G-E) * (h-f)-Minu; }

223. Rectangle Area

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