CSU 1354 Distinct Subsequences: Calculate the sum (dp) and csusubsequences of different Subsequences.
Question link: Click the open link
Description
Give a positive number, count the sum of the distinct subsequence of it, moreover, any subsequence shoshould not contain leading zeroes should t it is zero.
For example, if the number is 1022, the answer is 1 + 0 + 2 + 10 + 12 + 22 + 102 + 122 + 1022 = 1293.
Input
The first line has an integerT, Means there areTTest cases.
For each test case, there is only one line with a positive number, the number of the digits of it is in range [1,105].
The size of the input file will not exceed 5 MB.
Output
For each test case, print the desired answer in one line. Because the answer may be very large, you just need to print the remainder of it divided by 1000000007 instead.
Sample Input
3710221000000001
Sample Output
71293222222223
Ideas:
Dp [I] indicates the sum of subsequences ending with digit I, and num [I] indicates the number of subsequences ending with I.
import java.io.PrintWriter;import java.util.ArrayList;import java.util.Arrays;import java.util.Collections;import java.util.Comparator;import java.util.Iterator;import java.util.LinkedList;import java.util.PriorityQueue;import java.util.Scanner;import java.util.TreeSet;import java.util.Queue;public class Main {static int mod = 1000000007;static int N = 100010;long[] dp = new long[10], num = new long[10];String s;void work() {int T = cin.nextInt();while(T-- > 0) {s = cin.next();int len = s.length();for(int i = 0; i < 10; i++)dp[i] = num[i] = 0;for(int i = 0; i < len; i++){int x = s.charAt(i)-'0';long sum = 0, n = 0;for(int j = 0; j < 10; j++){sum += dp[j];n += num[j];}if(x>0)n++;dp[x] = sum*10%mod + n*x%mod;num[x] = n%mod;}long ans = 0;for(int i = 0; i < 10; i++)ans = (ans + dp[i])%mod;out.println(ans);}}Main() {cin = new Scanner(System.in);out = new PrintWriter(System.out);}public static void main(String[] args) {Main e = new Main();e.work();out.close();}public Scanner cin;public static PrintWriter out;int max(int x, int y) {return x > y ? x : y;}int min(int x, int y) {return x < y ? x : y;}double max(double x, double y) {return x > y ? x : y;}double min(double x, double y) {return x < y ? x : y;}long max(long x, long y) {return x > y ? x : y;}long min(long x, long y) {return x < y ? x : y;}static double eps = 1e-8;int abs(int x) {return x > 0 ? x : -x;}double abs(double x) {return x > 0 ? x : -x;}long abs(long x) {return x > 0 ? x : -x;}boolean zero(double x) {return abs(x) < eps;}}