Design a method for java interview questions to obtain random numbers in any range.

Design a method for java interview questions to obtain random numbers in any range.

When learning java basics, you may listen to the random numbers between 1 and 100 at most, so we should first write a random number between 1 and 100. The Code is as follows,

 

public class MathDemo1 {         public static void main(String[] args) {         for(int i=0;i<100;i++){         System.out.println(getRandom());         }}         public static int getRandom(){        int number = (int) (Math.random() * 100) + 1;return number;         }}

In this loop, we want to check whether the random number is correct for 100 times, so our interview questions are random numbers in any range, such as 200 to 300. This is a range. Let's take a look.

int number = (int) (Math.random() * 100) + 1

Can this code be written like this? int number = (int) (Math. random () * (100-0) + 1;

 

Where can we regard 0 as a starting variable? 100 when the maximum value of any number of tasks evolves into this way,

 

public class MathDemo1 {         public static void main(String[] args) {         for(int i=0;i<100;i++){         System.out.println(getRandom(200,300));         }}         public static int getRandom(int start,int end){        int number = (int) (Math.random() * (end-start+1)) + start;return number;         }}

OK.