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[Django]url Parameters/reverse and Httpresponseredirect

Source: Internet
Author: User
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Reference

You need to complete the following tasks 
- 访问http://127.0.0.1:8000/                  返回"hello maotai"或home.html- 访问http://127.0.0.1:8000/add/?a=1&b=2      返回之和- 访问http://127.0.0.1:8000/add2/2/3          返回值和- 访问http://127.0.0.1:8000/add2_v2/2/3       跳转到add2,并返回之和
Project Code Implementation

views.html Writing 
views.html#### 返回字符串def index(request):    return HttpResponse("hello maotai")#### url参数 ?a=1&b=2 方式传参def add(request):    a = request.GET['a']    b = request.GET['b']    c = int(a) + int(b)    return HttpResponse(c)#### url参数/2/3 方式传递def add2(request, a, b):    c = int(a) + int(b)    return HttpResponse(str(c))#### 重定向到add2, url的cname#### 模板解析也用到了reverse函数,解析谁? 解析html,将解析到的结果返回def add2_v2(request, a, b):    return HttpResponseRedirect(reverse('add2', args=(a, b)))#### 返回htmldef home(request):    return render(request, "home.html")
urls.py 
urlpatterns = [    path('', views.index),    path('home/', views.home),    path('add/', views.add),    path('add2/<int:a>/<int:b>', views.add2, name='add2'),    path('add2_v2/<int:a>/<int:b>', views.add2_v2, name='add2_v2'),    path('admin/', admin.site.urls),]
Home.html 
<!DOCTYPE html>

[Django]url Parameters/reverse and Httpresponseredirect

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