Find the odd number of times in an array where the number of other numbers appear even several times in an array where the number of odd occurrences

Find the number of odd times in an array with an even number of other numbers the public
class oddnum{
	
	//(1) array has only one number occurrences of the odd number of times public
	static void Get01 (Int[]arr)
	{
         int cur=0;
         for (int i=0;i<arr.length;i++)
         {
         	cur=cur^arr[i];
         }
         SYSTEM.OUT.PRINTLN (cur);

	}

	(2) The odd number of times public
	static void Get02 (Int[]arr)
	{
         int cur=0,oddone=0 is
         present in two numbers in the array; for (int i=0;i<arr.length;i++)
         {
         	cur^=arr[i];
         }
         int rightone=cur& (~cur+1);
         for (int i=0;i<arr.length;i++)
         {
         	if ((rightone&arr[i))!=0)
         	{
         		oddone^=arr[i];
         	}
         System.out.println (oddone+ "" + (Cur^oddone));
	}
	public static void Main (String[]args)
	{
		int[]arr={1,2,2,3,3,5,5};
		int[]arr2={1,3,3,3,5,5};
		GET01 (arr);
		Get02 (ARR2);


	}