Java Basics Review One, code block execution order

Source: Internet
Author: User

1 /**2 * Test of code block execution order3 * Execute sequential Static code block >MAIN code block > Construct code block > Constructor > Normal code block4  * @authorAdministrator5  * 6  */7  Public classClassDemo01 {8     Static {9System.out.println ("This is a static code block");Ten     } One     { ASystem.out.println ("This is a construction code block"); -     } -  the      PublicClassDemo01 () { -System.out.println ("This is a constructor"); -     } -  +      Public voidprint () { -System.out.println ("This is an ordinary code block"); +     } A  at     /** -      * @paramargs -      */ -      Public Static voidMain (string[] args) { -System.out.println ("This is a main code block"); -ClassDemo01 Classdemo =NewClassDemo01 (); in classdemo.print (); -     } to  +}

Java Basics Review One, code block execution order

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