License Plate Character Segmentation

Then the previous article, the above completed the Pai Chan positioning, then now the license plate character segmentation, the following program each step has a purpose to mark

%%%4.2 License plate Region thresholding (OSTU)
I=imread (' C:\Users\Administrator\Desktop\Des.jpg ');
I=rgb2gray (I);
Figure (1);
Subplot (2,1,1); Imshow (I);
Lev=graythresh (I);
BW=IM2BW (I,lev);
Subplot (2,1,2); Imshow (BW);

%%4.3.1 Plate Tilt Correction
% image tilt correction using the horizontal projection method
[N2,k2]=size (BW);
Xdata=zeros (1,N2);
Ydata=zeros (1,N2);
K1=1;
For L=1:1:N2
For K=1:1:K2
If BW (l,k) ==1
XData (K1) =l;
Ydata (K1) =k;
k1=k1+1;
Break
End
End
End

Res=fit (XData ', Ydata ', ' poly1 ');
P1=RES.P1;
R=imrotate (BW,P1);
Figure (2);
Subplot (2,1,1); Imshow (BW);
Subplot (2,1,2); Imshow (R);

%%%4.4 Word Segmentation min
The% character is projected downward, drawing the position of the character periodically
V=sum (R);
Figure (3);
Subplot (2,1,1);p lot (v);
Ma=max (v);
Length=size (v,2);
For I=1:1:length
If V (1,i) <0.1*ma
V (1,i) = 0;
End
End
Subplot (2,1,2);p lot (v);

Percent and then determine the starting and ending position of each character according to the pattern of vertical projection
Str=zeros (1,7);
Quit=zeros (1,7);
k=1;
For I=2:1:length
if (V (i-1) ==0) & (V (i) >0)
Str (k) =i;
Else
if (V (i-1) >0) & (V (i) ==0)
Quit (k) =i-1;
k=k+1;
Continue
End
End
End
Percent cut per character
Figure (4);
P1=r (:, str (1): Quit (1));
Subplot (4,2,1); Imshow (p1);
P2=r (:, str (2): Quit (2));
Subplot (4,2,2); Imshow (p2);
P3=r (:, str (3): Quit (3));
Subplot (4,2,3); imshow (p3);
P4=r (:, str (4): Quit (4));
Subplot (4,2,4); Imshow (p4);
P5=r (:, str (5): Quit (5));
Subplot (4,2,5); Imshow (p5);
P6=r (:, str (6): Quit (6));
Subplot (4,2,6); Imshow (P6);
P7=r (:, str (7): Quit (7));
Subplot (4,2,7); Imshow (P7);

Figure (1)

Figure (2)

Figure (3)

Figure (4)