Path problems when reading external files in Java programs

Transferred from: https://www.cnblogs.com/wt20/p/8320346.html

Projects often read some configuration files, so the GetResource method can play an important role

There are two main methods used, one is the bytecode file class class, the other is the ClassLoader class loader

There are two ways to use class classes:

1. Use "/" to get to the classpath path

2. Do not use "/" This is the relative path

ClassLoader class

Without the "/" notation, the classpath path is obtained.

Test code

public class Getresourcetest {public    static void Main (string[] args) {        System.out.println ( GetResourceTest.class.getResource ("/test.properties"). GetPath ());        System.out.println (GetResourceTest.class.getResource ("Test1.properties"). GetPath ());        System.out.println (GetResourceTest.class.getClassLoader (). GetResource ("Test.properties"). GetPath ());        System.out.println (GetResourceTest.class.getClassLoader (). GetResource ("/"));}    }

Results:

/e:/ideajava/studytest/out/production/studytest/test.properties
/e:/ideajava/studytest/out/production/studytest/com/waston/test/test1.properties
/e:/ideajava/studytest/out/production/studytest/test.properties
Null

Project Package Structure

The above is written by https://www.cnblogs.com/wt20/p/8320346.html Bloggers

Recent projects require processing of the database's historical data, and because of the lack of familiarity with the timing tasks of the Oracle database, a timed task is written using Java

In the program need to read a CTL file, but, if given a directory, to the client run time may be due to the file location error can not read to the file, try to use the virtual path, no success, search the Internet using this method can get to the directory, try to use, success.

Path problems when reading external files in Java programs