Python basics------How to "sort" dictionaries based on dictionary values

Requirements: Dictionary of {name: score}, sorted by score

Method One: Convert to Tuples, (91, "Zhang San") in the form of the sorted () function to sort

Method Two: Set the value of the key parameter in sorted ()

1 #-*-coding:utf-8-*-2 #mister into a random dictionary3  fromRandomImportRandint4d= {x:randint (60,101) forXinch "abcdxyz"}5 Print(d)6 #method One: Tuple form7 #Put the value in front because the sorted () sort by default is compared from the beginning8z =Zip (d.values (), D.keys ())9 #x = Zip (D.itervalues (), D.iterkeys ()) iteration type, save spaceTen #Sort Ones =sorted (z) A Print(s) -  - #method Two: sorted (key setting) theA =D.items () -s = sorted (a,key=LambdaX:x[1]) - Print(s)

Python basics------How to "sort" dictionaries based on dictionary values